SOLUTION: The perimeter of a rectangle is 32ft. The length is 8 ft. longer than the width find the dimensions. Write a system of linear equations solve the resulting system. Let x be the le

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: The perimeter of a rectangle is 32ft. The length is 8 ft. longer than the width find the dimensions. Write a system of linear equations solve the resulting system. Let x be the le      Log On


   

Question 717953: The perimeter of a rectangle is 32ft. The length is 8 ft. longer than the width find the dimensions. Write a system of linear equations solve the resulting system. Let x be the length and y be the width.
Answer by oscargut(2103) About Me  (Show Source):
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The perimeter of a rectangle is 32ft. The length is 8 ft. longer than the width find the dimensions. Write a system of linear equations solve the resulting system. Let x be the length and y be the width.

System:
2(x+y)=32
x = y+8
solution:
2(y+8+y)=32
2(2y+8)=32
2y+8=16
2y = 8
y = 4
x = 12
Answer: legth = 12 width = 4