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A 25-liter solution of alcohol in water is 72% alcohol. How many liters of an 80% solution must be added if the final solution is to be 75% alcohol?
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A 25-liter solution of alcohol in water is 72% alcohol. How many liters of an 80% solution must be added if the final solution is to be 75% alcohol?
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A 25-liter solution of alcohol in water is 72% alcohol. How many liters of an 80% solution must be added if the final solution is to be 75% alcohol?
Big thanks :* Answer by checkley79(3341) (Show Source):
You can put this solution on YOUR website! .72*25+.80X=.75(25+X)
18+.80X=18.75+.75X
.80X-.75X=18.75-18
.05X=.75
X=.75/.05
X=15 LITERS OF 80% SOLUTION IS REQUIRED.
PROOF:
.72*25+.80*15=.75(25+15)
18+12=.75*40
30=30