Question 717739: Luis and Julia have the same number of coins. Luis only has dimes and Julia has only quaters. If Julia has $1.80 more than luis does, how many coins does each have?
Answer by DrBeeee(684)   (Show Source):
You can put this solution on YOUR website! Let c = number of coins each has.
Let L = the value of Luis' coins, in cents
Let J = value of Julia's coins, in cents
Then we have
(1) J - L = 180
where we use 180 cents instead of $1.80.
Since Luis has only dimes, the value of his coins is 10*c, and Julia's quarters are worth 25*c. Put L and J into (1) to get
(2) 25*c - 10*c = 180 or
(3) 15*c = 180 or
(4) c = 12
Let's check this value using (1).
Is (25*12 - 10*12 = 180)?
Is (300 - 120 = 180)?
Is (180 = 180)? Yes
Answer: Luis and Julia each have 12 coins.
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