SOLUTION: Determine the missing coordinate for the point (x,(1/4))on the unit circle that in in quadrant II.

Algebra ->  Coordinate-system -> SOLUTION: Determine the missing coordinate for the point (x,(1/4))on the unit circle that in in quadrant II.      Log On


   

Question 717712: Determine the missing coordinate for the point (x,(1/4))on the unit circle that in in quadrant II.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
We're in quadrant II, so x < 0

x^2 + y^2 = 1

x^2 + (1/4)^2 = 1

x^2 + 1/16 = 1

x^2 = 1 - 1/16

x^2 = 16/16 - 1/16

x^2 = 15/16

x = -sqrt(15/16)... remember, x < 0

x = -sqrt(15)/sqrt(16)

x = -sqrt(15)/4

So x+=+-sqrt%2815%29%2F4