Question 717310: The length of a rectangle is 10 ft longer than twice the width. If the perimeter is 74 ft, find the length and width of a rectangle. Answer by mathworm7271(5) (Show Source):
You can put this solution on YOUR website! x=width
2x+10=length
Perimeter=2x+2(2x+10)
2x+4x+20
6x+20
Perimeter=74
Plug them in...
74=6x+20
Subtract 20 on both sides
54=6x
Divide both sides by 6
9=x
2(9)+10
18+10
28=length
9=width