SOLUTION: $5900 is invested, part at 10% and part of it at 8%. For a certain year, the total yield $ 534.00. How much was invested at 10% and at 8%?
ive tried substitution method but k
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ive tried substitution method but k
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Question 717147: $5900 is invested, part at 10% and part of it at 8%. For a certain year, the total yield $ 534.00. How much was invested at 10% and at 8%?
You can put this solution on YOUR website! $5900 is invested, part at 10% and part of it at 8%.
For a certain year, the total yield $ 534.00.
How much was invested at 10% and at 8%?
:
let x = amt invested at 10%
let y = amt at 8%
:
Two equations
:
Total amt
x + y = 5900
y = (5900-x)
:
and total interest
.10x + .08y = 534
:
In the above equation, substitute (5900-x) for y
.10x + .08(5900-x) = 534
.10x + 472 - .08x = 534
.10x - .08x = 534 - 472
.02x = 62
x = 62/.02
x = $3100 invested at 10%
:
You can find the amt invested at 8%
:
:
Check your solutions by finding the total interest from these amts
