SOLUTION: In four years, Steve's age will be two years less than twice Anne's age. Three years ago, Steve was three times as old as Anne was then. How old is each now?

Algebra ->  Customizable Word Problem Solvers  -> Age -> SOLUTION: In four years, Steve's age will be two years less than twice Anne's age. Three years ago, Steve was three times as old as Anne was then. How old is each now?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 716617: In four years, Steve's age will be two years less than twice Anne's age. Three years ago, Steve was three times as old as Anne was then. How old is each now?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
In four years, Steve's age will be two years less than twice Anne's age. Three years ago, Steve was three times as old as Anne was then. How old is each now?
---------
Equations:
s+4 = 2a-2
s-3 = 3(a-3)
------
Rearrange:
s = 2a-6
s = 3a-6
--------
That is a contradiction.
Ans: No solution
=======================
Cheers,
Stan H.