SOLUTION: Completely factor the polynomial 4x^3+12x^2+4x+12 The answer I have is (2x-3)(2x^2+3) I grouped the problem first and then i factored out the GCF from both groups. I followe

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Completely factor the polynomial 4x^3+12x^2+4x+12 The answer I have is (2x-3)(2x^2+3) I grouped the problem first and then i factored out the GCF from both groups. I followe      Log On


   



Question 716369: Completely factor the polynomial
4x^3+12x^2+4x+12
The answer I have is
(2x-3)(2x^2+3)
I grouped the problem first and then i factored out the GCF from both groups. I followed directions I wrote down from a similar problem so i am unsure if the same rules apply to this question
Thank You!

Found 2 solutions by Alan3354, solver91311:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Completely factor the polynomial
4x^3+12x^2+4x+12
The answer I have is
(2x-3)(2x^2+3)
I grouped the problem first and then i factored out the GCF from both groups. I followed directions I wrote down from a similar problem so i am unsure if the same rules apply to this question
-------------------
Multiply your answer, see if it works.
%282x-3%29%282x%5E2%2B3%29+=+4x%5E3+-+6x%5E2+%2B+6x+-+9
Doesn't match.

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


If you factor something and then multiply the factors you should get back to where you started. So let's see what happens.



Hmmm. Back to square 1.

First grouping:



Factor out of the first two terms, and out of the second two terms.



Now factor out:



John

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My calculator said it, I believe it, that settles it
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