SOLUTION: This is the question I'm struggling to solve. 7/12X - 1/4 = 5
Below is my attempt to solve. It doesn't look correct.
12 would be my common denominator
7/12X - 3/12X = 5
4/
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-> SOLUTION: This is the question I'm struggling to solve. 7/12X - 1/4 = 5
Below is my attempt to solve. It doesn't look correct.
12 would be my common denominator
7/12X - 3/12X = 5
4/
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Question 716329: This is the question I'm struggling to solve. 7/12X - 1/4 = 5
Below is my attempt to solve. It doesn't look correct.
12 would be my common denominator
7/12X - 3/12X = 5
4/12X = 5
1/3X =5 Answer by solver91311(24713) (Show Source):
Where did the X in the second term in the LHS come from? You can't just stick variables in any place that you find convenient.
Since you cannot add the term with the variable to the constant term, there is really no reason to find denominator common to them both. Your correct first step would be to add to both sides.
Now you need a common denominator, namely common between 1 (the understood denominator under the 5) and 4, namely 4.
Now multiply both sides by the reciprocal of the coefficient on the variable, namely
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
