SOLUTION: The width of a rectangle is 3 feet more than twice the length. If the perimeter is 60 feet, find the length and width of the rectangle.

Algebra ->  Rectangles -> SOLUTION: The width of a rectangle is 3 feet more than twice the length. If the perimeter is 60 feet, find the length and width of the rectangle.       Log On


   

Question 716220: The width of a rectangle is 3 feet more than twice the length. If the perimeter is 60 feet, find the length and width of the rectangle.
Answer by checkley79(3341) About Me  (Show Source):
You can put this solution on YOUR website!
P=2L+2W
W=2L+3
60=2L+2(2L+3)
60=2L+4L+6
60-6=6L
54=6L
L=54/6
L=9 FEET IS THE LENGTH.
W=2*9+3
W=18+3
W=21 FEET FOR THE WIDTH.
PROOF:
60=2*9+2*21
60=18=42
60=60