SOLUTION: find an equation of the hyperbola with vertices at (-6, 1) and (4, 1) and foci at (-8, 1) and (6, 1)

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: find an equation of the hyperbola with vertices at (-6, 1) and (4, 1) and foci at (-8, 1) and (6, 1)      Log On


   



Question 716101: find an equation of the hyperbola with vertices at (-6, 1) and (4, 1) and foci at (-8, 1) and (6, 1)
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
find an equation of the hyperbola with vertices at (-6, 1) and (4, 1) and foci at (-8, 1) and (6, 1)
***
Standard form of a hyperbola with horizontal transverse axis:
%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1, (h,k)=(x,y) coordinates of vertex.
y-coordinate of center=1
x-coordinate of center=(-6+4)/2=-1 (midpoint formula)
center: (-1, 1)
a=5 (distance from center to vertex, (-1 to - 6) on the horizontal transverse axis)
a^2=25
c=7 (distance from center to focus, (-1 to - 8) on the horizontal transverse axis)
c^2=49
c^2=a^2+b^2
b^2=c^2-a^2=49-25=24
Equation of given hyperbola:
%28x%2B1%29%5E2%2F25-%28y-1%29%5E2%2F24=1