SOLUTION: find three consecutive integers such that the product of the first two is 48
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Question 716055
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find three consecutive integers such that the product of the first two is 48
Answer by
CubeyThePenguin(3113)
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consecutive integers: (x-1), x, (x+1)
(x-1)(x) = 48
x^2 - x - 48 = 0
The solutions are not integers.
