Question 715999:  a shipment of 12 television sets  contains 3 defective sets. In how many ways can a hotel purchanse 5 of these sets and at least 2 of the defective sets? 
 Answer by stanbon(75887)      (Show Source): 
You can  put this solution on YOUR website! a shipment of 12 television sets contains 3 defective sets. In how many ways can a hotel purchanse 5 of these sets and at least 2 of the defective sets? 
------ 
Binomial Problem with n = 5 ; p(defective) = 1/4 ; p(not defective) = 3/4 
----------- 
P(2<= x <=5) = binomcdf(5,1/4,5)-binomcdf(5,1/4,1) = 0.3672 
========================== 
Cheers, 
Stan H. 
========================== 
  | 
 
  
 
 |   
 
 |