SOLUTION: I can't figure this out. Suppose to solve over [0,2pi) square root of 2sinx + cos2x=1

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Question 715828: I can't figure this out. Suppose to solve over [0,2pi)
square root of 2sinx + cos2x=1
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
What is in the square root?
sqrt%282%29%2Asin%28x%29+%2B+cos%282x%29=1?
sqrt%282sin%28x%29%29+%2B+cos%282x%29=1?
sqrt%282sin%28x%29+%2B+cos%282x%29%29=1?

Please re-post your question and make it clear what is in the square root.