SOLUTION: A movie theater charges $8 for an adult ticket and $5 for a student ticket. 1 night, 380 tickets were sold for a total of $2377. How many of each type were sold.

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: A movie theater charges $8 for an adult ticket and $5 for a student ticket. 1 night, 380 tickets were sold for a total of $2377. How many of each type were sold.      Log On


   

Question 715775:
A movie theater charges $8 for an adult ticket and $5 for a student ticket. 1 night, 380 tickets were sold for a total of $2377. How many of each type were sold.
Answer by checkley79(3341) About Me  (Show Source):
You can put this solution on YOUR website!
A+C=380
A=380-C
8A+5C=2377
8(380-C)+5C=2377
3040-8C+5C=2377
-3C=2377-3040
-3C=-663
C=-663/-3
C=221 CHILDREN'S TICKETS WERE SOLD.
A+221=380
A=380-221
A=159 ADULT TICKETS WERE SOLD.
PROOF:
8*159+5*221=2377
1272+1105=2377
2377=2377