SOLUTION: the greatest angle in a pair of suplementary angles that is differ by 36

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Question 715647:

the greatest angle in a pair of suplementary angles that is differ by 36
Answer by checkley79(3341) About Me  (Show Source):
You can put this solution on YOUR website!
X+Y=180
X-Y=36 ADD.
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2X=216
X=216/2
X=108 DEGREES FOR THE LARGER ANGLE.
108+Y=180
Y=180-108
Y=72 DEGREES FOR THE SMALLER ANGLE.
PROOF:
108-72=36
36=36