SOLUTION: Find the area of the triangle formed by the (x,y)-axes and the line with equation 4x+3y-12=0

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Question 715519: Find the area of the triangle formed by the (x,y)-axes and the line with equation 4x+3y-12=0
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
The x- and y-intercepts of the line with equation
4x%2B3y-12=0 <--> 4x%2B3y=12 are easy to find.
For x=0 --> 4%2A0%2B3y=12 --> 0%2B3y=12 --> 3y=12 --> y=4
gives you point (0,4) as the y-intercept.
For y=0 --> 4x%2B3%2A0=12 --> 4x%2B0=12 --> 4x=12 --> x=3
gives you point (3,0) as the x-intercept.
Those 2 points and point (0,0) , the origin, are the vertices of your triangle:

You could say that the length of the base of your triangle is b=3 units
and the height is h=4 units,
so the area (in square units) is
b%2Ah%2F2=3%2A4%2F2=highlight%286%29