Question 715517: Find an equation in general form of the perpendicular bisector of the line segment with endpoints A(7,-1) and B(-4,2)
Answer by mananth(16946)   (Show Source):
You can put this solution on YOUR website! A(7,-1) and B(-4,2)
mid point co-ordinates x=(7+(-4))/2=3/2
y=(-1+2)/2= =1/2
(3/2, 1/2)
A(7,-1) and B(-4,2)
slope = ((2-(-1))/(-4-7)
slope=- 3/11
the slope of line perpendicular to this line will have slope of 11/3
m=11/3 , point (3/2, 1/2)
y-(1/2) = 11/3( x-(3/2))
y-1/2 =11/3(2x-3)/2)
simplify
2*3(y-1/2) = 11(2x-3)
6y-3=22x-33
6y=22x-30
y=(11/3)x -5
|
|
|
