SOLUTION: I am trying to verify this equation: (1 + csc 3B/sec 3B) - cot 3B = cos 3B I thought by putting these two fractions together using the common denominator, and I got.... (1 +

Algebra ->  Trigonometry-basics -> SOLUTION: I am trying to verify this equation: (1 + csc 3B/sec 3B) - cot 3B = cos 3B I thought by putting these two fractions together using the common denominator, and I got.... (1 +      Log On


   

Question 715472: I am trying to verify this equation:
(1 + csc 3B/sec 3B) - cot 3B = cos 3B
I thought by putting these two fractions together using the common denominator, and I got....
(1 + csc 3B - cot 3B * sec 3B) all over sec 3B
This is where I get stuck......
Found 2 solutions by Alan3354, stanbon:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
I am trying to verify this equation:
(1 + csc 3B/sec 3B) - cot 3B = cos 3B
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The parentheses don't serve any purpose.
What is the numerator on the left side? csc? or 1 + csc?

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
verify this equation:
(1 + csc 3B/sec 3B) - cot 3B = cos 3B
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Multiply thru by sec(3B) to get:
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sec(3B) + csc(3B) - sec(3B)*cot(3B) = sec(3B)*cos(3B)
----
sec + csc - (1/cos)(cos/sin) = sec*cos
------
sec + csc - (1/sin) = 1
sec + csc - csc = 1
sec(3B) = 1
----
That does not verify the equation.
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Cheers,
Stan H.
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