SOLUTION:
Suppose that the length of one leg of a right triangle is 4 inches more than the length of the other leg. If the length of the hypotenuse is 20 inches, find the lengths of the
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Suppose that the length of one leg of a right triangle is 4 inches more than the length of the other leg. If the length of the hypotenuse is 20 inches, find the lengths of the
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Question 715413:
Suppose that the length of one leg of a right triangle is 4 inches more than the length of the other leg. If the length of the hypotenuse is 20 inches, find the lengths of the two legs.
Can someone show me how to solve this problem and the answer? Thank you Answer by checkley79(3341) (Show Source):
You can put this solution on YOUR website! A^2+B^2=C^2
X^2+(X+4)^2=20^2
X^2+X^2+8X+16=400
2X^2+8X+16-400=0
2X^2+8X-384=0
2(X^2+4X-192)=0
(X+16)(X-12)=0
X-12=0
X=12 IN. ANS. FOR SIDE A.
12+4=16 IN. ANS. FOR SIDE B.
PROOF:
12^2+16^2=20^2
144+256=400
400=400
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