SOLUTION: Could you please help me with this geometry problem? Problem: In triangle ABC, angle A is 5 times angle B, and angle C is 16 degrees less than angle B. What are the measures of

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Question 715391: Could you please help me with this geometry problem?
Problem: In triangle ABC, angle A is 5 times angle B, and angle C is 16 degrees less than angle B. What are the measures of the three angles?
My attempt: I tried to figure this problem out by forming an equation. I did A5=B
and got B/5. I took B/5 and tried the equation C- 16 degrees= B/5. I then multiplied 5 by each variable. I got 5c-80 degrees= B. I divided 5c and b by 5 and ended up with c-80 degrees= B/5... Here i got lost.. I know that i'm doing this wrong. I don't remember how to solve this problem...
Any help you could provide would be greatly appreciated!

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
USING ALGEBRA:
Let's call the measures of the angles (in degrees) A , B and C
We know that the measures of the angles of a triangle add up to 180%5Eo so
highlight%28A%2BB%2BC=180%29
We translate "angle A is 5 times angle B" as
A=5%2AB (or highlight%28A=5B%29 leaving out the optional middle dot symbol for multiplication).
We translate "angle C is 16 degrees less than angle B" as
highlight%28C=B-16%29
Now we put together all we know.
The sum of the three angles will be
%285B%29%2BB%2B%28B-16%29=180 (I put the expressions for A and C in in parentheses, but those parentheses are not needed).
5B%2BB%2BB-16=180 --> 7B-16=180 --> 7B-16%2B16=180%2B16 --> 7B=196 --> 7B%2F7=196%2F7 --> highlight%28B=28%29