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Question 71520This question is from textbook pre-algebra california edition
: 6y-10-y>14
This question is from textbook pre-algebra california edition
Answer by bucky(2189)   (Show Source):
You can put this solution on YOUR website! 6y-10-y>14
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You can treat this somewhat like an equation. What you want to do is get all the terms
containing y on the left side and all the numbers on the right side. Let's do it.
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Get rid of the -10 on the left side by adding +10 to it. But if you add +10 to one side
you also have to add +10 to the other side.
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When you do this the inequality becomes:
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6y - 10 + 10 - y > 14 + 10
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On the left side the +10 adds to the -10 to cancel out each other. And on the right side
the +10 adds to +14 to become +24. After these changes the inequality becomes:
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6y -y > 24
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On the left side you can combine the two y terms. Subtracting y from 6y results in an
answer of 5y and the inequality becomes:
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5y > 24
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Finally, you divide both sides by 5 so that only y is on the left side. The inequality
then becomes:
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y > 24/5
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And in decimals 24/5 = 4.8 which makes the inequality:
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y > 4.8
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This says that y is greater than 4.8 or 24/5, whichever you prefer.
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Don't forget when you multiply or divide both sides of an inequality by a negative
number, you have to change the inequality sign so that it points in the opposite direction.
This does not apply to this particular problem, but you might run into a problem that you
will have to remember this.
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I hope this gives you a little insight into working inequality problems.
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