SOLUTION: he strength of a beam varies directly as its width and the square of its depth. If the width changes by a factor of 2.7 and the depth changes by a factor of 2.5, determine the fact

Algebra ->  Rational-functions -> SOLUTION: he strength of a beam varies directly as its width and the square of its depth. If the width changes by a factor of 2.7 and the depth changes by a factor of 2.5, determine the fact      Log On


   



Question 715195: he strength of a beam varies directly as its width and the square of its depth. If the width changes by a factor of 2.7 and the depth changes by a factor of 2.5, determine the factor by which the strength of the beam changes.

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
S = strength of the beam
w = width of the beam
d = depth of the beam
k = variation constant
S=k%2Aw%2Ad%5E2
If we start with
w=w%5B1%5D and d=d%5B1%5D
the strength of the beam is
S%5B1%5D=k%2Aw%5B1%5D%2Ad%5B1%5D%5E2
If the we change width and depth to
w=w%5B2%5D=2.7w%5B1%5D and d=d%5B2%5D=2.5d%5B1%5D
the strength of the new beam is