SOLUTION: SOLVE: GIVEN A NUMBER SUCH THAT ONE IS 6 MORE THAN THE OTHER. FOUR TIMES LARGER ADDED TO 5 TIMES SMALLER IS 141. FIND THE NUMBERS.

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: SOLVE: GIVEN A NUMBER SUCH THAT ONE IS 6 MORE THAN THE OTHER. FOUR TIMES LARGER ADDED TO 5 TIMES SMALLER IS 141. FIND THE NUMBERS.      Log On


   

Question 715131: SOLVE: GIVEN A NUMBER SUCH THAT ONE IS 6 MORE THAN THE OTHER. FOUR TIMES LARGER ADDED TO 5 TIMES SMALLER IS 141. FIND THE NUMBERS.
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
x = y + 6
4x + 5y = 141

Substitute the first equation into the second equation.

4(y + 6) + 5y = 141
4y + 24 + 5y = 141
9y = 117
y = 13

solution: (x, y) = (19, 13)