SOLUTION: write an exponential function of the form y=ab^x whos graph passes trough the points, (2,5.888),(3,9.4208)

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: write an exponential function of the form y=ab^x whos graph passes trough the points, (2,5.888),(3,9.4208)      Log On


   



Question 71509: write an exponential function of the form y=ab^x whos graph passes trough the points, (2,5.888),(3,9.4208)
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
write an exponential function of the form y=ab^x whos graph passes trough the points, (2,5.888),(3,9.4208)
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5.888 = ab^2
9.4208 = ab^3
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Divide the 1st equation into the 2nd to get:
1.6 = b
Now, solve for "a" by substituting 1.6 for b
5.888 = a (1.6)^2
a= 5.888/(1.6)^2 = 2.3
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So, y=(2.3)(1.6)^x
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Cheers,
Stan H.