SOLUTION: I so badly need someones help asap. I have 6 problems i really need help with. Can someone show me step by steps to get to the answers? Please! 1)Use the given zero to find the

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: I so badly need someones help asap. I have 6 problems i really need help with. Can someone show me step by steps to get to the answers? Please! 1)Use the given zero to find the       Log On


   



Question 715021: I so badly need someones help asap. I have 6 problems i really need help with. Can someone show me step by steps to get to the answers? Please!
1)Use the given zero to find the remaining zeros of the function. h(x)=x^4-12x^3+40x^2+16x-240 zero;4-2i

2)If f(x)=ln x, g(x)=e^2x, an h(x)=x^7, find the following.
a)(f o g)(x). what is the domain of f o g?
b)(g o f)(x). what is the domain of g o f?
c)(f o h)(x). what is the domain of f o h?
3)Consider the functions f(x)=x^3-4 and g(x)=^3sqrt x+4.
a)find f(g(x))
b)find g(f(x))
c) determine whether the functions f and g are inverse of each other.
4)The Function f(x)=(2x)/(3x-5) is one to one. find its inverse and check your answer.
5)Solve the following exponential equation. 25^x+5^(x+1)-24=0
6)Solve the following logarithmic equation. log2(x+6)=3-log2(x-1)


PLEASE HELP ME!!

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
5)Solve the following exponential equation. 25^x+5^(x+1)-24=0
----------
25 = 5^2
25%5Ex%2B5%5E%28x%2B1%29-24=0
--> 5%5E%282x%29+%2B+5%5E%28x%2B1%29+=+24
2x*log(5) + (x+1)*log(5) = log(24)
2x + x+1 = log(24)/log(5)
3x = log(24)/log(5) - 1
x = log(24)/(3log(5)) - 1/3
----------------------------
6)Solve the following logarithmic equation. log2(x+6)=3-log2(x-1)
3+=+log%282%2C8%29
log2(x+6)=3-log2(x-1)
-->
x+6 = 8/(x+1)
etc
===============
3)Consider the functions f(x)=x^3-4 and g(x)=^3sqrt x+4.
I don't know what ^3sqrt x+4 means.