SOLUTION: What is the smallest counting number that is divisible by 4, 5, 6, 9 and 28?

Algebra ->  Divisibility and Prime Numbers -> SOLUTION: What is the smallest counting number that is divisible by 4, 5, 6, 9 and 28?      Log On


   

Question 714886: What is the smallest counting number that is divisible by 4, 5, 6, 9 and 28?
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Finding these facts will help you:
4=2%5E2
5=5%5E1
6=2%5E1%2A3%5E1
9=3%5E2
28=2%5E2%2A7%5E1

Look at all the prime number factors involved in the set of numbers listed. You need to use each prime factor the greatest number of times that it is present in the list. THAT gives the product you are looking for.

prime-----------highest expon
2?----------------2
3?----------------2
5?----------------1
7?----------------1
I left the last couple of steps undone.