SOLUTION: Find an equation of the line containing the given pair of points. 1. (2, 5) and (4,7) 2. (0, -5) and (3,0) 3. (-4, -7) and (-2,-1)

Algebra ->  Linear-equations -> SOLUTION: Find an equation of the line containing the given pair of points. 1. (2, 5) and (4,7) 2. (0, -5) and (3,0) 3. (-4, -7) and (-2,-1)      Log On


   



Question 714865: Find an equation of the line containing the given pair of points.
1. (2, 5) and (4,7)
2. (0, -5) and (3,0)
3. (-4, -7) and (-2,-1)

Answer by MathLover1(20849) About Me  (Show Source):
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1. (2, 5) and (4,7)

Solved by pluggable solver: FIND EQUATION of straight line given 2 points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (2, 5) and (x2, y2) = (4, 7).
Slope a is a+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29+=+%287-5%29%2F%284-2%29+=+1.
Intercept is found from equation a%2Ax%5B1%5D%2Bb+=+y%5B1%5D, or 1%2A2+%2Bb+=+3. From that,
intercept b is b=y%5B1%5D-a%2Ax%5B1%5D, or b=5-1%2A2+=+3.

y=(1)x + (3)

Your graph:





2. (0, -5) and (3,0)
Solved by pluggable solver: FIND EQUATION of straight line given 2 points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (0, -5) and (x2, y2) = (3, 0).
Slope a is .
Intercept is found from equation a%2Ax%5B1%5D%2Bb+=+y%5B1%5D, or 1.66666666666667%2A0+%2Bb+=+-5. From that,
intercept b is b=y%5B1%5D-a%2Ax%5B1%5D, or b=-5-1.66666666666667%2A0+=+-5.

y=(1.66666666666667)x + (-5)

Your graph:





3. (-4, -7) and (-2,-1)
Solved by pluggable solver: FIND EQUATION of straight line given 2 points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (-4, -7) and (x2, y2) = (-2, -1).
Slope a is a+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29+=+%28-1--7%29%2F%28-2--4%29+=+3.
Intercept is found from equation a%2Ax%5B1%5D%2Bb+=+y%5B1%5D, or 3%2A-4+%2Bb+=+5. From that,
intercept b is b=y%5B1%5D-a%2Ax%5B1%5D, or b=-7-3%2A-4+=+5.

y=(3)x + (5)

Your graph: