SOLUTION: What two numbers are twice as far from 40 as they are from 70

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Question 714329: What two numbers are twice as far from 40 as they are from 70
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
THE FIFTH GRADER WAY:
That number could be in between 40 and 70,
or could be larger than 70.
(It cannot be less than 40 because that would put it close to 40 than to 70).
If it's in between, it should be 2%2F3 of the way from 40 to 70,
so you have gone 2 thirds of the way, but you have 1 third of the way to go.
Since that way is 70-40=30 , 1%2F3 of that way is 10, and
2%2F3 of that is 20 .
The number between 40 and 70, that is 10 away from 70, and
20 away from 40 is
40%2B20=highlight%2860%29.
If the number is larger than 70, and
going from 40 to that number is twice as far as
going from 70 to that number,
then 70 is half way there, and the distance from 40 to 70,
70=40=30 ,
is the same as from 70 further to the number,
so the number is 30 past 70 .
It is 70%2B30=highlight%28100%29

TWO WAYS THAT LOOK MORE LIKE ALGEBRA:
A number x is
abs%28x-40%29 from 40 and
abs%28x-70%29 from 70 .
We know that
abs%28x-40%29=2%2Aabs%28x-70%29
At this point,
we can just square both sides of the equal sign and worry about eliminating any possible extraneous solution later.
Or we could examine what those absolute values could be and work for each case.

Squaring both sides we get
%28x-40%29%5E2=2%5E2%2A%28x-70%29%5E2 --> x%5E2-80x%2B1600=4%28x%5E2-140x%2B4900%29 --> x%5E2-80x%2B1600=4x%5E2-560x%2B19600 --> 4x%5E2-x%5E2-560x%2B80x%2B19600-1600=0 --> 3x%5E2-480%2B18000=0
Dividing both sides by 3 we get
x%5E2-160%2B6000=0
If we are good at factoring, we factor to get
%28x-60%29%28x-100%29=0 with solutions
highlight%28x=60%29 and highlight%28x=100%29
If we cannot factor, we apply the quadratic formula:
x+=+%28-%28-160%29%2B-+sqrt%28%28-160%29%5E2-4%2A1%2A6000+%29%29%2F%282%2A1%29+
x+=+%28160%2B-+sqrt%2825600-24000+%29%29%2F2+
x+=+%28160%2B-+sqrt%281600+%29%29%2F2+ --> x+=+%28160%2B-+40%29%2F2
with solutions
x=%28160%2B40%29%2F2 --> x=200%2F2 --> highlight%28x=100%29 and
x=%28160-40%29%2F2 --> x=120%2F2 --> highlight%28x=60%29 .

Examining case by case the absolute values:
For x%3E70 ,
abs%28x-40%29%3E0 so abs%28x-40%29=x-40 and
abs%28x-70%29%3E0 so abs%28x-70%29=x-70
abs%28x-40%29=2%2Aabs%28x-70%29 transforms into
x-40=2%2A%28x-70%29 --> x-40=2x-140 --> x-40%2B140-x=2x-140%2B140-x --> -40%2B140=2x-x --> highlight%28x=100%29
For x%3C40 ,
abs%28x-40%29%3C0 so abs%28x-40%29=-%28x-40%29 and
abs%28x-70%29%3C0 so abs%28x-70%29=-%28x-70%29
abs%28x-40%29=2%2Aabs%28x-70%29 transforms into
-%28x-40%29=2%2A%28-%28x-70%29%29 and multiplying times %28-1%29 both sides of the equal sign we get
x-40=2%2A%28x-70%29 as above,
which gives us the solution x=100 as above,
but as we had started with x%3C40,
we did not find a solution that fit the case x%3C40.
For x such that 40%3Cx%3C70 ,
abs%28x-40%29%3E0 so abs%28x-40%29=x-40 and
abs%28x-70%29%3C0 so abs%28x-70%29=-%28x-70%29
abs%28x-40%29=2%2Aabs%28x-70%29 transforms into
x-40=2%2A%28-%28x-70%29%29 --> x-40=2%28-x%2B70%29%29 --> x-40=-2x%2B140%29%29 --> x-40%2B2x%2B40=-2x%2B140%2B2x%2B40%29%29 --> x%2B2x=140%2B40 --> 3x=180 --> 3x%2F3=180%2F3 --> 3x=180 --> highlight%28x=60%29 .