SOLUTION: One of two complementary angles is 6 degrees smaller than twice the other angle. Find the measure of each angle.
I have tried:
2x-6=180 -> add 6 to both sides
2x=186 -> divi
Algebra ->
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-> SOLUTION: One of two complementary angles is 6 degrees smaller than twice the other angle. Find the measure of each angle.
I have tried:
2x-6=180 -> add 6 to both sides
2x=186 -> divi
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Question 713727: One of two complementary angles is 6 degrees smaller than twice the other angle. Find the measure of each angle.
I have tried:
2x-6=180 -> add 6 to both sides
2x=186 -> divide both sides by 2
x = 93
And:
90-2x-6=180 -> add like terms
84-2x=180 -> subtract 84 from both sides
-2x=106 -> divide both sides by -2
x=93
According to the back of my book the answers should be 32 and 58 but I can't seem to get there and it doesn't show how to do it.
You can put this solution on YOUR website! Let the two angles be A and B.
A = 2B - 6 [6 degrees smaller than twice the other angle]
Since the two angles are complementary, A + B = 90 -> A = 90 - B
Solve for B:
90 - B = 2B - 6
3B = 96
B = 32
Therefore A = 90 - 32 = 58
Ans: 32, 58
