Question 71295: Some one please help
Determine the vertex of y = x^2 -8x +22
Please show how you do this
Thank you Answer by funmath(2933) (Show Source):
You can put this solution on YOUR website! Some one please help
Determine the vertex of y = x^2 -8x +22
:
One way to find the vertex is tho put the equation in vertex form by completing the square: , where (h,k)=(x,y) of the vertex.
y=(x^2-8x+___)-___+22
y=(x^2-8x+(-8/2)^2)-(-8/2)^2+22
y=(x-4)^2-(-4)^2+22
y=(x-4)^2-16+22
y=(x-4)^2+6
The vertex, (h,k)=(4,6)
:
Another way to do this is to use the formula to find the x value of the vertex.
a=1 and b=-8
Now plug that value back into the original equation to find the y-value.
Once again the vertex is (4,6)
Use whichever method you prefer and your teacher allows.
Happy Calculating!!!!
(