SOLUTION: elaine added 3 lbs. of peanuts to a 15 lb. mixture containing peanuts and raisins. if the original mixture was 25% peanuts, what is the percent if peanuts in the new mixture?

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Question 712924: elaine added 3 lbs. of peanuts to a 15 lb. mixture containing peanuts and raisins. if the original mixture was 25% peanuts, what is the percent if peanuts in the new mixture?
Found 2 solutions by josgarithmetic, stanbon:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
p for pounds peanuts to add to original mixture, 3 pounds
v for pounds original mixture, 15 pounds
H for percent peanuts percent, 100%
L for percent peanuts in the mix before adding the 3 pounds of it, 25%
T UNKNOWN % peanuts in the mix after adding the 3 pounds of it
M = 3+15=18 pounds of final mixture

Formula for T is straight-forward.
highlight%28T=%28H%2Ap%2BL%2Av%29%2F%28M%29%29
We know everything to calculate and find T.

Percent Peanuts = %28100%2A3%2B25%2A15%29%2F18 %
=37.5% peanuts

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
elaine added 3 lbs. of peanuts to a 15 lb. mixture containing peanuts and raisins. if the original mixture was 25% peanuts, what is the percent o6.75f peanuts in the new mixture?
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Equation:
peanuts + peanuts = peanuts
-------
1*3 + 0.25*15 = x(3+15)
Multiply thru by 100 to get:
300 + 25*15 = 1800x
x = 675/1800
Percent = 37.5
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Cheers,
Stan H.
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