SOLUTION: Differentiate y=4^(csc^2)x +sqrt(x)*log (base of 3) x I differentiated the 4csc and got ln(4^(csc)^2)x then csc^2x *ln4. How do I do the Sqrt? Wouldnt I do the same t

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Differentiate y=4^(csc^2)x +sqrt(x)*log (base of 3) x I differentiated the 4csc and got ln(4^(csc)^2)x then csc^2x *ln4. How do I do the Sqrt? Wouldnt I do the same t      Log On


   

Question 712700: Differentiate
y=4^(csc^2)x +sqrt(x)*log (base of 3) x
I differentiated the 4csc
and got
ln(4^(csc)^2)x
then csc^2x *ln4.
How do I do the Sqrt? Wouldnt I do the same thing with Log (base of 3) x? Change that to ln3/ lnx?
Answer by princessleia(1) About Me  (Show Source):