You can put this solution on YOUR website! sqrt(3)*sin(theta) + cos(theta) = 1
sqrt(3)/2*sin(theta)+1/2*cos(theta)=1/2 dividing both sides by 2
cos(30)sin(theta) + sin(30)cos(theta) =1/2 => as sqrt(3)/2 = cos30 and 1/2 is sin30
sin(theta +30) = 1/2 as we know that sin(a+b)= sin(a)cos(b) + cos(a) sin(b)
theta +30 = 30 taking sin inverse both sides
theta = 0
(