SOLUTION: I am having problems solving first degree equations in my pre-algebra math book.One of the problems is like this.6z - 1/3 =5/3 .If you could please help me by any way of understand
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Question 71259This question is from textbook pre-algebra
: I am having problems solving first degree equations in my pre-algebra math book.One of the problems is like this.6z - 1/3 =5/3 .If you could please help me by any way of understanding this problem and how to solve with fractions cause I keep getting 1/6 and the book seys that it is 1/3.THANK YOU VERY MUCH This question is from textbook pre-algebra
You can put this solution on YOUR website! Your question gives us to solve the equation :-
6z - 1/3 = 5/3
see the point in these "solve the equation" problems whether there are fractions involved or not is to separate the unknown number ( in this case z)
side from all other numbers so that only that unknown numbers remains alone that side .We do this by adding , subtracting , multiplying , dividing corresponding numbers . When you solve a little higher level problems then you do something more than just addding, subtracting, etc. but you dont need them for this problem.
So this way you get the value of the unknown number which is the answer.
for example:-
6z - 1/3 = 5/3
6z - 1/3 + 1/3 = 5/3 + 1/3
6z = 6/3
6z = 2
6z/6 = 2/6
z = 1/3 Answer.
You can put this solution on YOUR website! Solve for z: First, to get rid of the fractions, you want to multiply everything by the common denominator. This is 3. Perform the multiplication. Simplify. Now add 1 to both sides of the equation. Finally, you divide both sides by 18. Simplify.
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