SOLUTION: How many liters of pure water should be mixed with a 16-L solution of 90% acid to produce a mixture that is 90% water?

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Question 712536: How many liters of pure water should be mixed with a 16-L solution of 90% acid to produce a mixture that is 90% water?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
How many liters of pure water should be mixed with a 16-L solution of 90% acid to produce a mixture that is 90% water?
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Equation:
water + water = water
0.10*16 + 1*x = 0.90(16 + x)
Multiply thru by 100 to get:
10*16 + 100x = 90*16 + 90x
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10x = 80*16
x = 8*16 = 128 liters (amt. of pure water needed)
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Cheers,
Stan H.
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