Question 712308: I am not sure how to do this. It says find the real zeros in the this problem
f(x)= x^3+4x^2-5x
Thanks!
Melissa Answer by unlockmath(1688) (Show Source):
You can put this solution on YOUR website! Hello,
Let's set this f(x)= x^3+4x^2-5x up as:
0= x^3+4x^2-5x
Now factor:
0= x(x^2+4x-5)
Now factor again:
0= x(x+5)(x-1)
Solve for x
x=-5
x=1
Make sense?
RJ
www.math-unlock.com