SOLUTION: Dave is twice as old as Rick. Ten years ago the sum of their ages was 40. How old are they now?

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Question 712175:
Dave is twice as old as Rick. Ten years ago the sum of their ages was 40. How old are they now?
Found 2 solutions by checkley79, MathTherapy:
Answer by checkley79(3341) About Me  (Show Source):
You can put this solution on YOUR website!
D=2R
D-10+2R-10=40
2R-10+2R-10=40
4R-20=40
4R=40=20
4R=60
R=60/4
R=15 AGE OF RICK NOW.
D=2*15=30 AGE OF DAVE NOW.
PROOF:
30-10+2*15-10=40
20+30-10=40
50-10=40
40=40

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Dave is twice as old as Rick. Ten years ago the sum of their ages was 40. How old are they now?

Let Rick's current age be R

Then Dave's current age = 2R

Ten years ago, Rick was R - 10, and Dave was: 2R - 10

Therefore, R - 10 + 2R - 10 = 40

3R - 20 = 40

3R = 60

R, or Rick's current age = 60%2F3, or highlight_green%2820%29

Dave's current age = 2(20), or highlight_green%2840%29

You can do the check!!

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