Question 711964: If it is a parabola, give it's vertex, focus, and directrix; if it is an ellipse, give it's center, vertices, and foci; if it's a hyperbola, give it's center, vertices, foci, and asymptotes
The problem: x^2 + 4y = 4
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! If it is a parabola, give it's vertex, focus, and directrix; if it is an ellipse, give it's center, vertices, and foci; if it's a hyperbola, give it's center, vertices, foci, and asymptotes
The problem:
x^2 + 4y = 4
x^2 = -4y+4
x^2=-4(y-1)
This is an equation of a parabola that opens down.
Its standard form: (x-h)^2=-4p(y-k), (h,k)=(x,y) coordinates of the vertex
vertex: (0,1)
axis of symmetry:x=0 or y-axis
4p=4
p=1
focus: (0,0)(p-distance below vertex on the axis of symmetry)
directrix: y=2 (p-distance above vertex on the axis of symmetry)
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