SOLUTION: A, B are two light source 100m apart. A is twice as strong as B. P is a point between A, B. Intensity of illumination varies inversely as the square of the distance from the light
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Question 71149: A, B are two light source 100m apart. A is twice as strong as B. P is a point between A, B. Intensity of illumination varies inversely as the square of the distance from the light source. Find the length of AP so that the point P is the darkest
thank you Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! A, B are two light source 100m apart. A is twice as strong as B. P is a point between A, B. Intensity of illumination varies inversely as the square of the distance from the light source. Find the length of AP so that the point P is the darkest
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I am going to try to solve this graphically. Arbitrarily assign a value of 200 at
10 ft from A and 100 at 90 ft from A, or 10 ft from B.
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The x axis from 1 to 10 represents 100 meters (10 meters per unit of x)
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Let y = light intensity
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I came up with the following equation: y = (200/x^2) + (100/(10-x)^2)
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Graphing this:
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you can see the minimum intensity occurs between 5 and 6 which is between 50 and
60 meters from A. About 56 meter from A to p would be the darkest.
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Sorry I messed this up the first time, hope this helps
