Question 711404: How do I solve this problem?
x^3+3x^3-4x-12=0
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! How do I solve this problem?
x^3+3x^2-4x-12=0
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I graphed the cubic and found a root at x = -2
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Use synthetic division to find the other zeroes:
-2)....1....3....-4....-12
.......1....1....-6...|..0
Quotient: x^2 + x -6
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Solve x^2 + x -6 = 0
Factor:(x+3)(x-2) = 0
Zeroes: x = -2, x = 2, x = -3
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Cheers,
Stan H.
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