SOLUTION: The probability that Sue will live on campus and buy a new car is 0.37.
If the probability that she will live on campus is 0.73, find the probability that she will buy a new car,
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-> SOLUTION: The probability that Sue will live on campus and buy a new car is 0.37.
If the probability that she will live on campus is 0.73, find the probability that she will buy a new car,
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Question 711111: The probability that Sue will live on campus and buy a new car is 0.37.
If the probability that she will live on campus is 0.73, find the probability that she will buy a new car, given that she lives on campus. Answer by Dickiedannie(6) (Show Source):
You can put this solution on YOUR website! Use formula: P(B/A)= (P(A and B))/P(A)
Thus,let for Sue to live on Campus be L and Buy a new car be N
then you have P(N/L)= (P(L and N))/P(L)
From the question we obtain P(L and N)=0.37, P(L)=0.73
Input the probabilities to the Formula:
P(N/L)= (P(L and N))/P(L)=0.37/0.73=0.5068 to (4.S.F)
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