Question 710916: flying into the wind, a helicopter takes 15 min to travel 15 kilometers. The return takes 12 minutes. If the wind speed and direction remain constant during the trip, write and solve a system of equation to find the speed of the wind (in Kpm) and speed of the helicopter (in KPM).
I tired i got it wrong please help me to see the right direction
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! flying into the wind, a helicopter takes 15 min to travel 15 kilometers. The return takes 12 minutes. If the wind speed and direction remain constant during the trip, write and solve a system of equation to find the speed of the wind (in Kpm) and speed of the helicopter (in KPM).
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Against wind DATA:
distance = 15 km ; time = 15 min ; rate = d/t = 1 km/min
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With wind DATA:
distance = 15 km ; time = 12 min ; rate = d/t = 15/12 = 5/4 km/min
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Equations:
p + w = (5/4) km/min
p - w = 1 km/min
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Add and solve for "p":
2p = 9/4
p = 9/8 km/min (speed of the plane in still air)
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Solve for "w":
p - w = 1
w = p -1 = (9/8)-1 = 1/8 km/min (speed of the wind)
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Cheers,
Stan H.
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