SOLUTION: The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times the length of the base. If the perimeter is 29 cm, find the length of one of the equal legs.

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times the length of the base. If the perimeter is 29 cm, find the length of one of the equal legs.      Log On


   

Question 71091: The length of one of the equal legs of an isosceles triangle is 8 cm less than 4 times the length of the base. If the perimeter is 29 cm, find the length of one of the equal legs.
Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
let x be the equal sides then the perimeter is (base+2x) & x=(4b-8)
29=b+2(4b-8)
29=b+8b-16
29=9b-16
9b=29+16
9b=45
b=45/9
b=5 for the base . thus the equal sides are
4*5-8
20-8
12 for the equal sides
proof
29=5+2*12
29=5+24
29=29