SOLUTION: I need help. For the following problem I found no solution: 2log2 (x+6) - log2 16 = 2 heres my work: log2 x^2+36-16 = 2 x^2+20 = 2^2 x^2+20 = 4 x^2=-16 then there is

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: I need help. For the following problem I found no solution: 2log2 (x+6) - log2 16 = 2 heres my work: log2 x^2+36-16 = 2 x^2+20 = 2^2 x^2+20 = 4 x^2=-16 then there is       Log On


   

Question 71074: I need help. For the following problem I found no solution:
2log2 (x+6) - log2 16 = 2
heres my work:
log2 x^2+36-16 = 2
x^2+20 = 2^2
x^2+20 = 4
x^2=-16
then there is no real number for the square root of -16

Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
True there is no real number root but there is a root!
x^2=-16
x=4i