SOLUTION: Factor completely: 27x^6-8y^9

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Question 71067: Factor completely: 27x^6-8y^9
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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Factor completely: 27x^6 - 8y^9
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Factor as the difference of cubes: (x^3 - y^3) = (x - y)(x^2 + xy + y^2)
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That would be: (27x^6 - 8y^9) = (3x^2 - 2y^3) (9x^4 + 3x^2*2y^3 + 4y^6)
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Or: (27x^6 - 8y^9) = (3x^2 - 2y^3) (9x^4 + 6x^2y^3 + 4y^6)