SOLUTION: 50 ml of an 11%saline solution was mixed with 30 ml of a 75% saline solution. what is the total amount of concentration of the new mixture?

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Question 710659:
50 ml of an 11%saline solution was mixed with 30 ml of a 75% saline solution. what is the total amount of concentration of the new mixture?
Answer by checkley79(3341) About Me  (Show Source):
You can put this solution on YOUR website!
.11*50+.75*30=80x
5.5+22.5=80x
28=80x
x=28/80
x=.35 or 35% mixture.
Proof:
.11*50+.75*30=80*.35
5.5+22.5=28
28=28