SOLUTION: Factor completely over the imaginary number: x^4-3x^2-40

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Question 71062: Factor completely over the imaginary number: x^4-3x^2-40
Answer by checkley75(3666) About Me  (Show Source):
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x^4-3x^2-40
(x^2-8)(x^2+5) USING THE QUADRATIC EQUATION WE GET
X=(0+-SQRT[-4*1*-8])/2
X=(+-SQRT[+32])/2
X=(+-SQRT32}/2
X=(+-5.657)/2
X=5.657/2
X=2.828 ANSWER
X=-5.657/2
X=-2.828 ANSWER
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X=(0+-SQRT[0-4*1*5])/2
X=(+-SQRT-20)/2
X=(+-4.47i)/2
X=+4.47I/2
X=2.235i ANSWER
X=-4.47i/2
X=-2.235i ANSWER