SOLUTION: we started with 17 gallons of antifreeze that was 90% water and 10% antifreeze. We added 2 gallons of pure water and one gallon of pure antifreeze. Determine what percentage of the

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: we started with 17 gallons of antifreeze that was 90% water and 10% antifreeze. We added 2 gallons of pure water and one gallon of pure antifreeze. Determine what percentage of the      Log On

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Question 710614: we started with 17 gallons of antifreeze that was 90% water and 10% antifreeze. We added 2 gallons of pure water and one gallon of pure antifreeze. Determine what percentage of the resulting mix is water and what percent is antifreeze.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
we started with 17 gallons of antifreeze that was 90% water and 10% antifreeze. We added 2 gallons of pure water and one gallon of pure antifreeze. Determine what percentage of the resulting mix is water and what percent is antifreeze.
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Equation:
water + water = water
0.90*17 + 1*2 = x(17+2)
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90*17 + 100*2 = 19x
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x = 91.05% (percent of water in the mix)
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100-91.05 = 8.95% (percent of antifreeze in the mix)
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Cheers,
Stan H.