SOLUTION: Please can someone help me with this? Three consecutive integers are such that the first plus one-half the second plus seven less than twice the third is 2101. What are the integer
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Question 71056This question is from textbook
: Please can someone help me with this? Three consecutive integers are such that the first plus one-half the second plus seven less than twice the third is 2101. What are the integers? This question is from textbook
You can put this solution on YOUR website! Three consecutive integers
x, x+1, x+2
:
the first plus one-half the second plus seven less than twice the third is 2101.
x + .5(x+1) + 2(x+2) - 7 = 2101
:
What are the integers?
x + .5x + .5 + 2x + 4 - 7 = 2101
:
x + .5x + 2x + .5 + 4 - 7 = 2101
:
3.5x - 2.5 = 2101
:
3.5x = 2101 + 2.5
:
x = 2103.5/3.5
:
x = 601 is the 1st integer
:
Check:
601 + .5(602 + 2(603) - 7 =
601 + 301 + 1206 - 7 = 2101
